Question

3
5. p(x) = 69+11x – x² + x°, g(x) = x +3​

Answer 1

Step-by-step explanation:

Given,

p(x) = 69 + 11x - x^2 + x^0

P(x) = 69 + 11x - x^2 + 1

p(x) = -x^2 + 11x + 70

g(x) = x + 3

∴ put x + 3 = 0

x = -3

Now, put value of x in the polynomial

p(x) = -(-3)^2 + 11(-3) + 70

= -9 - 33 + 70

= -42 + 70

= 38

∴ r(x) = 38

and x + 3 is not a factor of the polynomial

Hope it will help you

Mark my answer as brainliest

Answer 2

P(x)= 69+11x-x^2+x^0

P(x)= 69+11x-x^2+1. [x^0=1]

P(x)= 11x-x^2+70

Putting x=-3. [g(x)=0

x+3=0

x=-3 ]

P(x)= 11×(-3)-(-3)^2+70

P(x)= -33-9+70

P(x)= -42+70

P(x)= 38

So r(x) is 38.

Therefore, x+3 is a factor.