Question

3/5 part of a pole is in mud. 3/10 of it is in water. and the rest 3 meters is above the water level. find out the height of the complete pole.
Guys Help me please!!

Answer 1

Answer:

30 m

Step-by-step explanation:

Let the length of the pole be x

Then the length of the pole in mud = 3x/5

Length of the pole in water = 3x/10

According to the question

x - [ 3x/5 + 3x/10] = 3

x - [6x/10 + 3x/10] = 3

x - 9x /10 = 3

10x/10 - 9x/10 = 3

x/10 = 3

x = 30 m

Answer 2

Answer:

Step-by-step explanation:

Concept:

The concept of basic mathematical functions will help us to find out the answer of the given question.

Given:

The part of $\frac{3}{5}$ of the pole is in mud.

The part of $\frac{3}{10}$ of the pole is in water.

The rest of $3 meters$ is above the water level.

To Find:

We have to find out the total height of the pole mentioned in the question.

Solution:

Consider that the total height of the pole is $x$.

The part which is in the mud is $\frac{3x}{5}$ .

The part which is in the water is $\frac{3x}{10}$ .

The height of the part which is above the water level is $3 m$.

From the above data,we can express the statement as:

$\frac{3x}{5} + \frac{3x}{10}+3=x$

The L.C.M of $5$ and $10$ is $10$ . Then the L.H.S is $\frac{6x+3x+30}{10}$

After the sum of the numerators , The L.H.S will be $\frac{9x+30}{10}$

Now the expression is $\frac{9x+30}{10}=x$

Multiply $10$ with the R.H.S and we will get $9x+30=10x$

After further calculation,  $10x-9x=30$ .

The value of $x$ is $x=30$ .

The total height of the poles is $30m$ .

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