Math, asked by rajput4423, 1 year ago

3^502-3^500+16/(3^500+2)=?​

Answers

Answered by knjroopa
6

Answer:

8

Step-by-step explanation:

Given  

3^502-3^500+16/(3^500+2)=?

ANSWER

We need to solve by simplifying.

Now divide both numerator and denominator by 3^500

So after dividing we get

3^2 – 1 + 16/3^500/1 + 2/3^500

9 – 1 + 0 / 1 + 0 (Since the fractions are negligible and very small it is 0)

8 / 1

= 8

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