3^502-3^500+16/(3^500+2)=?
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Answered by
6
Answer:
8
Step-by-step explanation:
Given
3^502-3^500+16/(3^500+2)=?
ANSWER
We need to solve by simplifying.
Now divide both numerator and denominator by 3^500
So after dividing we get
3^2 – 1 + 16/3^500/1 + 2/3^500
9 – 1 + 0 / 1 + 0 (Since the fractions are negligible and very small it is 0)
8 / 1
= 8
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