Chemistry, asked by adityaayushi2712, 1 month ago

3.5g of solute is present in 35g of saturated aqueous solution at 298K. Find the solubility of the solute at this temperature

Answers

Answered by piyushsahu624

1

Answer:

the solubility of the solute at this temperature 10g

Explanation:

Mass of solute = 3.5g

Mass of solvent = 35g

Mass of solute /mass of solvent *100=solubility

3.5/35*100=10g

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