Question

3√5x^2 +25x-10√5 solve by Quadratic Formula ​

Answer 1

Step-by-step explanation:

3√5x² +25x +10√5= 0.

3√5x² +15x + 10x +10√5= 0.

3x(√5x + 5) + 2√5(√5x + 5)= 0

(3x +2√5) (√5x + 5) = 0

(3x +2√5) = 0   or  (√5x + 5) = 0

3x = -2√5     or √5x = -5

Answer 2

Answer:

hey frnd here is ur answer

Step-by-step explanation:

: 3root5x^2 +25x+ 10 root 5

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2sum = 25x

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2sum = 25xno.s are = 15x , 10x

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2sum = 25xno.s are = 15x , 10x( 3√5x^2 + 15x) ( 10x + 10√5)

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2sum = 25xno.s are = 15x , 10x( 3√5x^2 + 15x) ( 10x + 10√5)3√5x(X+ √5) +10( X + √5)

3root5x^2 +25x+ 10 root 5product = ac= 3 √5x^2 X 10√5= 150x^2sum = 25xno.s are = 15x , 10x( 3√5x^2 + 15x) ( 10x + 10√5)3√5x(X+ √5) +10( X + √5)(3√5x + 10) ( X+ √5)

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