Question

3х 5y 2 3 -2 х 13 + у 2 = 3 6​

Answer 1

Step-by-step explanation:

Maximum height of a projectile is 300m when it is projected at an angle 60o from horizontal. Find out maximum height of this projectile when it is projected at an angle 30o from horizontal with same speed.

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Answer 2

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$\rm{13 + {y}^{2} = 36}$

$\to \rm{ {y}^{2} = 36 - 13}$

$\to \rm{ {y}^{2} = 23 }$