Question

3(5z-7)+2(9z-11)=4(8z-7)-111

Answer 1

5z+9z+8z(-7-11-111)=3+2+4
22z-129=9
22z=9+129
22z=138
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Answer 2

3(5z-7)+2(9z-11)= 4(8z-7)-111

15z-21 + 18z-22 = 32z-28-111

33z-43 = 32z-139

transpose,

33z-32z = -139+43

z = -96