Question

(׳+6ײ+2×+44)÷(×+2)

Answer 1

The zero of g(x)=1−2x is x=21

Now, by remainder theorem the remainder should be f(21)

∴f(21)=(21)3−6(21)2+2(21)−4

=(81)−6(41)+1−4

=(81)−(46)−3

=81−12−24

=-835

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add this as brainly list please