Question

3/√6-3√2 rationalize​

Answer 1

Answer:

$\frac{3}{ \sqrt{6} - 3 \sqrt{2} } \\ = \frac{3}{ \sqrt{6} - 3 \sqrt{2} } \times \frac{ \sqrt{6} + 3 \sqrt{2} }{ \sqrt{6} + 3 \sqrt{2} } \\ = \frac{3 \sqrt{6} + 9 \sqrt{2} }{6 - 18} \\ = \frac{ - 3 \sqrt{6} }{ 12} + \frac{ - 9 \sqrt{2} }{12} \\ =$