Question

³√6 , ⁴√12, √5, ⁶√2 arrange them in descending order​

Answer 1

Answer:

Step-by-step explanation:

SOLUTION:-

•The orders of the above surds are 3, 6 and 4.

•The least common multiple of (3, 6 and 4) is 12.

•So, we have to make the order of each surd as 12.

Then,

³√4  =  ³×⁴√(44)  =  ¹²√256

⁶√5  =  ⁶ײ√(52)  =  ¹²√25

⁴√6  =  ⁴׳√(63)  =  ¹²√216

•Now, the given two surds are expressed in the same order.

•Arrange the radicands in ascending order :

25, 216, 256  

Then,

¹²√25, ¹²√216, ¹²√256

•Therefore, the ascending order of the given surds is

⁶√5, ⁴√6, ³√4