3^-6/7*4^-3/7*9^3/7*2^6/7 ÷2^2+2^0+2^-2
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Question :- Given above in image .
Solution :- Refer to image .
formula used :-
In first step :-
- (a^m)^n = (a)^(m * n)
- a^(-m) = 1/a^m
In second step :-
- a^m * a^n = a^(m + n)
- a^0 = 1
In third step :-
- Additive inverse .
In fourth step :-
- a^0 = 1 { so, 1 + 1 = 2 }
therefore,
→ Final answer = (8/21)
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