Math, asked by bihanimohit24, 1 month ago

3^-6/7*4^-3/7*9^3/7*2^6/7 ÷2^2+2^0+2^-2​

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Answers

Answered by RvChaudharY50
16

Question :- Given above in image .

Solution :- Refer to image .

formula used :-

In first step :-

  • (a^m)^n = (a)^(m * n)
  • a^(-m) = 1/a^m

In second step :-

  • a^m * a^n = a^(m + n)
  • a^0 = 1

In third step :-

  • Additive inverse .

In fourth step :-

  • a^0 = 1 { so, 1 + 1 = 2 }

therefore,

→ Final answer = (8/21)

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Answered by 46mishra
23

Answer:

please mark me as brainlist

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