Question

3^-⁶/⁷*4^-³/⁷*9^³/⁷*2^⁶/⁷÷2²+2⁰+2^-²

Indices chapter.........
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Answer 1

Answer:-

This is the required solution.

$\sf\frac{ {3}^{ \frac{ - 6}{7} } \times {4}^{ \frac{ - 3}{7} } \times {9}^{\frac{ 3}{7}} \times {2}^{ \frac{6}{7} } }{ {2}^{2} + {2}^{0} + {2}^{ - 2} }$

$\sf = \frac{ {3}^{ \frac{ - 6}{7} } \times {( {2}^{2} )}^{ \frac{ - 3}{7} } \times {( {3}^{2} )}^{\frac{ 3}{7}} \times {2}^{ \frac{6}{7} } }{4 +1 + \frac{1}{4} }$

$\sf = \frac{ {3}^{ \frac{ - 6}{7} } \times {2}^{ \frac{ - 6}{7} } \times {3}^{\frac{6}{7}} \times {2}^{ \frac{6}{7} } }{4 +1 + \frac{1}{4} }$

$\sf = \frac{ {3}^{ \big(\frac{ - 6}{7} + \frac{6}{7} \big)} \times {2}^{ \big( \frac{ - 6}{7} + \frac{6}{7} \big) }}{4 +1 + \frac{1}{4} }$

$\sf = \frac{ {3}^{0} \times {2}^{0} }{ \frac{21}{4} }$

$\sf = \frac{1 \times 1}{ \frac{21}{4} }$

$\sf = \frac{1}{ \frac{21}{4} }$

$\sf = \frac{4}{21}$

Hence, the required answer is 4/21.

Answer 2

Answer:

hope the above pic helps u in ur question