Question

3 + 6 + 9 + 12 + ......... + 300 =
a. 900
b. 1515
c. 15150
d. 1200

Answer 1

>> We know that SUM (k) moving k from 1 to n is
>> to n is equal to =
>> 1+2+3+4+5+ ....... +n = n(n+1)/2. So 1+2+3+ .......
>> +100 = 100(101)/2
>> = 1050 -------- (1).
>>
>> And now 3+6+9+12+15+ ....... +300 = SUM (3k)
>> moving k from 1 to 100.
>> But SUM(3k)=3SUM(k) moving k from 1 to 100.
>>
>> Finally : 3SUM(k) = 3(1+2+3+4+5+....... + 100) =
>> 3(1050) = 3150 .



Therefore, the correct answer is 3150.

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Thanks.

Answer 2

a. is 570
b. is 1185
c. is 14820 and
d. is 870