Question

3+6+9+12...+333=?
May I know it's answer.......

Answer 1

Answer:

3+6+9+......+333

here in the AP, a= 3, d= 3, an=333

An= a+(n-1)d

333= 3+(n-1)3

330/3=n-1

n=111

Sum= n/2(a+an)

111/2 ×(3+333)=111×336/2=111×168=1848

Step-by-step explanation:

Answer 2

Answer:

a=3

l= 333

d= 3

sum= n/2×(a+l)

n=111

put the values