√3,√6,√9,√12 does it form an AP....IF yes/no prove.....
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This is not in AP.
Because common difference is not equal.
√6-√3=√3(√2-1)
Second term common difference
√9-√6=√3(3√3-√2)
We can see common difference is not equal
Because common difference is not equal.
√6-√3=√3(√2-1)
Second term common difference
√9-√6=√3(3√3-√2)
We can see common difference is not equal
deeksharai2000:
i wanted the steps
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