Question

3+ 6+9+ ... +300, Find the sum of the given equation.

Answer 1

a = 3

d = 3

L = 300

=> a + (n-1) d = 300

=> 3 + (n-1) (3) =300

=> (n-1) (3) = 297

=> n-1 = 99

=> n = 100

Now,

Required sum = n/2 ( a + L)

= 100 /2 ( 3 + 300)

= 50 × 303

= 15150

Answer 2

ANSHWER

[YOUR ANSHWER]

GIVEN→↓

a → 3

d →3

L → 300




→ANSHWER←




→ a + (n-1) d →300

→ 3 + (n-1) (3) →300

→(n-1) (3) → 297

→ n-1 → 99

\ n }100

Now,

Required sum → n/2 ( a + L)

=→100 /2 ( 3 + 300)

→ 50 × 303

→ 15150

THANKS☺