√3 ,√6, √9 are in ap
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if they are in AP then √6-√3 must be equal to √9-√6
√6-√3 = √3(√2-1) = √3(0.4)
√9-√6 = √3(√3-√2) = √3(0.4)
hence both are equal so they are in AP
please mark it as the brainliest answer
√6-√3 = √3(√2-1) = √3(0.4)
√9-√6 = √3(√3-√2) = √3(0.4)
hence both are equal so they are in AP
please mark it as the brainliest answer
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