Question

3
6. a and ß are the zeroes of polynomial 6x^2-X-2 and find the value of 1/a and 1/b​

Answer 1

$\huge{\mathcal{\green{Answer}}}$

Sum of the zeroes = -b/a= -(-1)/6=a+b

Product of the zeroes = c/a=-2/6=ab

Solving :

1/a+1/b= a+b/ab = 1/6/-2/6=1/-2

Answer 2

Here is your answer ❤️....