3.6 g of a gas at 27°C occupied the same volume
as 0.2 g of
H2
gas at 127°C and at the same
pressure. What is the molar mass of gas?
Answers
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3
Answer:
Explanation:
Ideal gas Eq
PV = nRT
since P and V are constt
n1/T1 = n2/T2 = PV/R
n1/300 = (0.2/2)/400
n1/300 = 1/4000
n1 = 3/40 = 3.6/M
M = 3.6 * 40/3 = 48g/mol
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