Question

3) 6 years ago, Mahima's mother was 3 times as old as
Mahima. After 5 years, she will be twice as old as Mahima.
Present age in years) of Mahima's mother is
A) 44
B) 41
C) 39,
D) 17
A imate
not
A morbove​

Answer 1

Given : 6 years ago, Mahima's mother was 3 times as old as Mahima.

After 5 years, she will be twice as old as Mahima.

To Find : Present age (in years) of Mahima's mother is

A) 44

B) 41

P) 39

D) 17​

Solution:

Mahima present age = A

Mahima mother [resent age = B

6 years ago, Mahima's mother was 3 times as old as Mahima.

=> B - 6 = 3(A - 6)

=> B = 3A  - 12

After 5 years, Mahima's mother will be twice as old as Mahima.

=> B + 5 = 2(A + 5)

=> B  = 2A + 5

3A  - 12 = 2A + 5

=> A = 17

B  = 2A + 5 = 2* 17 + 5 = 39

Present age (in years) of Mahima's mother is  39 Years

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