3.65 gm HCl is dissolved in 103.65gm hcl solution calculate Molality of this solution ?
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Answered by
3
given mass of HCl= 3.65 g
Then the no. of moles of HCl is= 3.65/36.5
=0.1 moles
now, molality= no. of moles of solute/ wt. of solvent ( in kg)
=0.1 x 1000/103.65
=0.9647 molal
Hope it helped
Answered by
0
Answer:
0.001 m
Explanation:
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