Question

- 3.6V
calculate the power disipated in
civuit ? R1=12,R2=16,R3=10, anser
​

Answer 1

Step-by-step explanation:

r1=5ohm

r2 = 10 \: ohmr2=10ohm

r3 = 30 \: ohmr3=30ohm

Current through R1,

i1 = \frac{v}{r1} = \frac{12}{5} = 2.4 \: ai1=

r1

v

=

5

12

=2.4a

Current through R2,

i2 = \frac{v}{r2} = \frac{12}{10} = 1.2 \: ai2=

r2

v

=

10

12

=1.2a

Current through R3,

i3= \frac{v}{r3} = \frac{12}{30} = 0.4 \: ai3=

r3

v

=

30

12

=0.4a

Total current across the circuit is the sum of of all currents flowing through the individual resistors.

i = i1 + i2 + i3 = 2.4 + 1.2 + 0.4 = 4 \: ai=i1+i2+i3=2.4+1.2+0.4=4a

Equivalent resistance across the parallel combination is,

\frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} = \frac{1}{5} + \frac{1}{10} + \frac{1}{30} = \frac{1}{3}

r

1

=

r1

1

+

r2

1

+

r3

1

=

5

1

+

10

1

+

30

1

=

3

1

r = 3 \: ohmr=3ohm