Question

(3.6x10^-5) divided (1.8x10^2)
answer is given in standard form

Answer 1

$\bold{\huge{\fbox{\color{Maroon}{♡Hello♡}}}}$

AnSwer:

The standard form of$(3.6 \times {10}^{ - 5} ) \div (1.8 \times {10}^{2} )$

is 0.0000002

SoLutiOn:

We have to write $(3.6 \times {10}^{ - 5} ) \div (1.8 \times {10}^{2} )$

in standard form.

$= \frac{3.6 \times 10^{-5}}{1.8 \times 10^{2}}$

By dividing 3.6 by 1.8 we get “2”, hence the above equation becomes,

$=\frac{2 \times 10^{-5}}{10^{2}}$

We know that $\frac{x^{a}}{x^{b}}=x^{a-b}$

Therefore the above equation becomes,

$=2 \times 10^{-5-2}$

$=2 \times 10^{-7}$

Since the exponent of 10 is negative , therefore 7 zeros are written on the left hand side of the number.

= 0.0000002

Hence the standard form is $\left(3.6 \times 10^{-5}\right) \div\left(1.8 \times 10^{2}\right)$

is 0.0000002.

$\bold{\huge{\fbox{\color{Purple}{♡Thanks♡}}}}$

Answer 2

Answer:

Step-by-step explanation: