Question

3,7,11,15,19- - - - -79 . find the 10th term from last

Answer 1

question

=> 3, 7, 11 , 15 , 19.........79

to find

10 term from last

=> we can reversing the ap

=> the new ap will be

79 , 75 , 71 ,.......

solution

first term = a = 79

common difference = (-4)

T 10 terms = a + 9d

=> 79 + 9( -4)

=> 79 - 36

=> 43

=> T 10 terms of ap = 43

Answer 2

QUESTION:

3,7,11,15,19- - - - -79 . find the 10th term from last

TO FIND :

$</u><u>\</u><u>bold</u><u> </u><u>{</u><u>10th \: term \: from \: last</u><u>}</u><u>$

FORMULA USED :

$</u><u>\</u><u>h</u><u>u</u><u>g</u><u>e</u><u>\</u><u>o</u><u>r</u><u>a</u><u>n</u><u>g</u><u>e</u><u> </u><u>{</u><u>last \: term(n) \: = l - (n - 1)d</u><u>}</u><u>$

where;

l = last term

d = common difference

now come to main question ;

Here;

l = 79

d = 7-3

d = 5

Using the formula;

$l(10) = 79 - (10 - 1)5 \\ l(10) = 79 - 9 \times 5 \\ l(10) = 79 - 45 \\ l(10) = 34$

$\huge\pink {10th \: term \: from \: last \: is \: 34}$

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