Math, asked by 5111eeff, 10 months ago

(3/7)^-2+1÷(3/7)^-1=[(3/7)^-1]-7

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Answered by Krsanketpatel7542

1

Step-by-step explanation:

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Answered by bkpaf225

0

Answer:3/7^-2+1=3/7^+7

3/7^-1=3/7^7

Hence,3/7=[3/7^7]-1

Step-by-step explanation:

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