Question

(-3,7,2) and (2,4,-1) find distance between the points 3d geometery​

Answer 1

The distance between the two points (x1, y1, z1) and (x2, y2, z2) in an XYZ plane is given by,

√[(x1 - x2)² + (y1 - y2)² + (z1 - z2)²]

Here, we are given,

(x1, y1, z1) = (-3, 7, 2)

(x2, y2, z2) = (2, 4, -1)

Then, the distance between them is,

√[(- 3 - 2)² + (7 - 4)² + (2 - (-1))²]

= √[(-5)² + 3² + 3²]

= √[25 + 9 + 9]

= √43

Hence √43 is the answer.

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