Question

(3/7)^2x-1 =9/49 find the x​

Answer 1

Answer:

$( \frac{3}{7} ) {}^{2x - 1} = \frac{9}{49}$

$( \frac{3}{7} ) {}^{2x - 1} = ( \frac{3}{7}) {}^{2}$

2x-1 = 2

2x = 2+1

2x = 3

x = 3/2

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Answer 2

Answer:

(3/7)^2x-1 =9/49

(3/7)^2x-1=3^2/7^2

(3/7)^2x-1=(3/7)^2. [a2x=a6]

2x-1 = 2 [2x=6]

2x=2+ 1 [x=3]

x=3/2