Question

(3+√7)(-3-√7) are the root of quadric equation find the quadratic eqyation

Answer 1

Heya !!!




( 3 + root 7 ) ( 3 - root 7) are the roots of the quadratic equation.





Sum of zeroes = ( 3+ root7)(3-root7) = 6





And,





Product of zeroes = ( 3 + root 7)( 3 - root 7)




=> (3)² - ( root7)²




=> 9 -7 = 2




Therefore,




Required quadratic equation = X²-(Sum of zeroes)X + Product of zeroes




=> X² - ( 6)X + (2)



=> X² -6X + 2






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Answer 2

Required quadratic equation :
=x^2(sum of roots)x+(product of roots)=0
=x^2{(√3-7)+(√3+7)}x+{(√3-7)(√3+7)}=0
=x^2-(2√3)x+{(√3)^2-(7)^2}=0
=x^2-2√3x+(3-49)=0
=x^2-2√3x-46=0 Ans

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