Question

3√7/4√7

rationalise above expression please ​

Answer 1

Answer:

= (√7+√3)/{(√9x3)+√(9 x7)-√(4 x7)-√(16 x3)}

= (√7+√3)/(3√3+3√7–2√7–4√3)

= (√7+√3)/(√7–√3)

Rationalising the denominator we have

= {(√7+√3)/(√7–√3)}{(√7+√3)/(√7+√3)}

= (7+3+2√21)/(7–3)

= (10+2√21)/4

= (5+√21)/2