Question

3/7 + 4/9 + (-6)
please answer the question ​

Answer 1

i dont know the anwerhug

Answer 2

Simplify :

$\boxed{ \sf \dfrac{3}{7} \: + \: \dfrac{4}{9} \: + (- 6)}$

$\sf \: So \: first \: of \: all \: we \: will \: solve \: : \: \sf \dfrac{3}{7} \: + \: \dfrac{4}{9}$

Before adding them we have to make the denominator same.

$\dfrac{3}{7} \: \times \: \dfrac{9}{9} \: = \: \dfrac{27}{63}$

$\dfrac{4}{9} \: \times \: \dfrac{7}{7} \: = \: \dfrac{28}{63}$

$\dfrac{27 + 28}{63} \: = \green{ \: \dfrac{55}{63} }$

$\sf \: Now, \: \dfrac{55}{63} \: + \: ( - 6)$

$\sf \: \dfrac{55}{63} \: - \: \dfrac{6}{1}$

Here also, before Subtracting them we have to make the denominator same.

$\dfrac{6}{1} \: \times \: \dfrac{63}{63} \: = \: \dfrac{378}{63}$

$\dfrac{55 - 378}{63} \: = \: \dfrac{ - 323}{6}$

$\purple{\boxed { \sf \: \red{ So, \: the \: answer \: is} \: \green{ \dfrac{ - 323}{6} }}}$