Question

3/7+(-6/11)+(-8/21)+(5/22)​

Answer 1

3/7+(-6/11) + (-8/21) + (5/22)

Taking L.C.M. of the denominators 7, 11, 21

and 22 and then solving it.

L.C.M. of 7,11, 21 and 22 2'3'7*11

= 462

= (462/7)3 - (462/1)*6 - (462/21)*8+(462/22)*5

(198/462) - (252/462) - (176/462)+(105/462)

= (303/462) - (428/462)

= (-125/462)

Answer 2

Step-by-step explanation:

Solution:

Given expression,

3/7+(-6/11)+(-8/21)+(5/22)

→ [(3/7) + (-8/21)] + [(-6/11) + (5/22)]

(क्रमविनिमेयता और साहचर्यता के उपयोग से)

→ [{(3*3) + (-8) * 1}/21] + [{(-6) * 2 + 5 * 1}/22]

→ [{9 + (-8)}/21] + [(-12 + 5)/22]

→ (1/21) + (-7/22)

→ {1 * 22 * + (-7) * 21}/462

→ (22 - 147)/462

→ -125/462 Ans.