Question

3.7 gm of oxalic acid is present in its 0.5 dm³ solution,find normality of solution​

Answer 1

Answer:

Solution :

Step I. Calculation of molarity of the sodium <br> Mass of oxalic acid

<br> Molar mass of oxalic acid

<br> No. of moles of oxalic acid

<br> Volume of solution

<br> Molarity of solution

<br>

<br>

<br> Step II. Calculation of normality of the acid solution <br> Basicity of oxalic acid from the formula = 2 <br> Equivalent mass of oxalic acid

<br> No. of equivalent of oxalic acid

<br>

<br> Note : The normality of the acid solution can also be calculated with the help of relation : <br> Normality of acid = Molarity of acid

Basicity