3.7 litre of 1 molar Naoh solution is mixed with another 5 litre of 0.3 molar Naoh solution then the molarity of the resulting solution is
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Answer:
when same type of solution are mixed then we add them...when different kind of solution are mixed we substract them...here naoh and naoh are base so we will add their concentration
Explanation:
M=n/vol
m1v1+m2v2 divide by
V1+V2
1×3.7+0.3×5 divide by 3.7+5
3.7+1.5÷by8.7
5.2÷8.7
0.597
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