Question

3.7^x=(0.37)^y=1000 show that x^-1-y^-1=1000

Answer 1

Answer:

x = 1

Step-by-step explanation:

to say that a series is in AP the common difference should be equal

a2 - a1 = a3 - a2

x - 2 = a1

4x - 1 = a2

5x + 2 = a3

verification(see this image)

x - 2 = 1 - 2 = -1

4x - 1 = 4(1) - 1 = 4 - 1 = 3

5x + 2 = 5(1) + 2 = 5 + 2 = 7

the AP is -1, 3, 7

common difference

a2 - a1 = a3 - a2

3 - (-1) = 7 - 3

3 + 1 = 7 - 3

4 = 4