Math, asked by bhatprati, 1 year ago

*ಹೋಟೇಲಿನಲ್ಲಿ 3 ಜನ ಫ್ರೆಂಡ್ಸ್ ಊಟ ಮಾಡ್ತಾರೆ,*

*75ರೂ ಬಿಲ್ ಬಂತು.*

*3 ಜನ 25+25+25 ವೈಟರ್'ಗೆ ಕೊಟ್ರು.*

*ವೈಟರ್ ಮ್ಯಾನೆಜರ್'ಗೆ ಕೊಟ್ಟ.*

*ಮ್ಯಾನೇಜರ್ 5ರೂ ಡಿಸ್'ಕೌಂಟ್ ಕೊಟ್ಟ.*

*ವೈಟರ್ 2ರೂ ಇಟ್'ಕೊಂಡು,*

*3 ಜನಕ್ಕೂ 1,1,1ರೂ ವಾಪಾಸ್ ಕೊಟ್ಟ,*

*ಅಂದ್ರೆ ಒಬ್ಬೊಬ್ಬರಿಗೆ 24,24,24,ರೂ ಆಯ್ತು.*

*ಸೋ 24+24+24=72+ವೈಟರ್ 2=74.*

*ಹಾಗಾದರೆ ಇನ್ನು1ರೂ ಎಲ್ಲೋಯ್ತು? ಟ್ಯಾಲೆಂಟ್ ಇದ್ದರೆ ಆನ್'ಸ್ವರ್ ಮಾಡಿ.*


bhatprati: Itz k ,,I will translate

Answers

Answered by prmkulk1978
0
English Version of question:
Three friends went to a hotel. The bill was Rs 75/-
Each one contributed Rs.25/-.
The waiter took the bill to the cashier.
The cashier was happy & decided to give them a discount of Rs.5/- & asked the waiter to return them Rs.5/-.
Now the waiter was confused. How to distribute Rs 5 among 3 persons?
He kept Rs 2 in his pocket & gave one rupee to each one of the 3 persons.
So initially each one had contributed Rs.25. Now as they are given 1 rupee back, their contribution reduces to Rs 24.
They all contributed Rs 24 -- that is 24x3=72 & 2 rupees are in the waiters pocket.
The total becomes 74. But they had paid Rs 75.
Where is the remaining 1 rupee?.

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So friends, it's simple.
We are getting confused by adding 2 rupees in the last instead of subtracting.
Solution:
Total Bill= 75 rs
Friend's share = 25+25+25=75
Discount =Rs 5
So New Bill 75-5=70 rupees
3 rupees waiter returned that makes the bill in the persons mind as :75-3=72
So each friend contributed 24 rupees each
24x3=72
Waiter kept 2 rupees 72-2=70 rupees which the correct new bill amount after discount.
So where is the question of 1 rupee difference.
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