Question

(3/7p^2+4q^2)× 7(p^2-3/4q^2)

Answer 1

Answer:

$(\frac{3}{ {7p}^{2} } + 4 {q}^{2} ) \times 7( {p}^{2} \frac{ - 3}{4 {q}^{2} } ) \\ = \frac{3 + 28 {p}^{4} }{7 {p}^{2} } \times 7 {p}^{2} \frac{ - 3}{4 {q}^{2} } \\ = 3 + 28 {p}^{4} \times \frac{ - 3}{4 {q}^{2} } \\ = \frac{ - 9 - 84 {p}^{4} }{4 {q}^{2} }$

Jai Shree Ram