Question

3(7x+1/5x-3) - 4(5x-3/7x+1) = 11

Answer 1

On Putting (7x+1)/(5x-3)=y

SOLUTION:

3y-4/y=11

(3y×y-4)/y=11

3y^2-4=11y

3y^2-11y-4=0

3y^2-12y+y-4=0

3y(y-4)+1(y-4)=0

(3y+1)(y-4)=0

y=-1/3 or y=4

VERIFICATION:-

y=-1/3 :-

3(7x+1)=-1(5x-3)

21x+3=-5x+3

21x+5x=3-3

26x=0

x=0/26

x=0

y=4

7x+1=4(5x-3)

7x+1=20x-12

7x-20x=-12-1

-13x=-13

x=13/13

x=1

HENCE THE VALUE OF x=0 and x=1

HOPE IT WILL HELP YOU!