Math, asked by Anonymous, 8 months ago

3[(7x+1)/(5x-3)]-4[(5x-3)/(7x+1)]=11
solve for x by quadratic formula...........

Answers

Answered by erajireddy6

1

Answer:

Given:

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0(3y +1) = 0 or (y - 4)= 0 y = -1/3 or y = 4

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0(3y +1) = 0 or (y - 4)= 0 y = -1/3 or y = 4Case 1. y = -3 7x+1/5x-3 = 3 3(7x+1) = -1(5x-3) 21x +3 = -5x +3

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0(3y +1) = 0 or (y - 4)= 0 y = -1/3 or y = 4Case 1. y = -3 7x+1/5x-3 = 3 3(7x+1) = -1(5x-3) 21x +3 = -5x +321x +5x = 3 -3

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0(3y +1) = 0 or (y - 4)= 0 y = -1/3 or y = 4Case 1. y = -3 7x+1/5x-3 = 3 3(7x+1) = -1(5x-3) 21x +3 = -5x +321x +5x = 3 -326x = 0 x = 0/26

Given:3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11On Putting 7x+1/5x-3 = y, 3y - 4/y = 11 (3y x y -4)/y = 1 3y? - 4 = 11y 3y2 - 11 y - 4 = 0 3y2 -12y + y - 4 = 0 3y ( y - 4) +1(y - 4)= 0 (3y +1) (y - 4)= 0(3y +1) = 0 or (y - 4)= 0 y = -1/3 or y = 4Case 1. y = -3 7x+1/5x-3 = 3 3(7x+1) = -1(5x-3) 21x +3 = -5x +321x +5x = 3 -326x = 0 x = 0/26x=0

Case 2. y = 4 7x+1/5X-3 = 4 7x+1 = 4(5x-3) 7x +1 = 20x -12 7x - 20x = -12-1

Case 2. y = 4 7x+1/5X-3 = 4 7x+1 = 4(5x-3) 7x +1 = 20x -12 7x - 20x = -12-1-13x = -13

Case 2. y = 4 7x+1/5X-3 = 4 7x+1 = 4(5x-3) 7x +1 = 20x -12 7x - 20x = -12-1-13x = -13x = 13/13 x=1

Case 2. y = 4 7x+1/5X-3 = 4 7x+1 = 4(5x-3) 7x +1 = 20x -12 7x - 20x = -12-1-13x = -13x = 13/13 x=1Hence, the value of x= O or x = 1.

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