Question

3(7x+1/5x-3) -4(5x-3/7x+1)=11 solve the following quadratic equation.​

Answer 1

Answer:

3(7x+1/5x-3) -4(5x-3/7x+1) =11

(21x+3/5x-3)-(20x-12/7x+1)=11

now,

(7x+1)(21x+3) -(5x-3)(20x-12) /35x2-16x-3=11

147x2+42x+3-(100x2-120x+36)/35x2-16x-3=11

47x2+162x-33/35x2-16x-3=11

47x2+162x-33=385x2-176x-33

47x2-385x2+162x+176x-33+33=0

-338x2+338x=0

338x2-338x=0

338x2=338x

x2=338x/338

x2=x

x=√x

Answer 2

Answer:

hope this will help you . ..........