3+8+13+18+......sum of the 8 terms of this A.P is
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Here, First term a=3 and common difference d=5
Now,
t
n
=a+(n−1)d
⇒t
n
=3+(n−1)×5
⇒t
n
=3+5n−5
⇒t
n
=5n−2
Hope it helps.....
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