Question

3,8,13 is a arithmetic sequence check weather 116 is a term of this sequence

Answer 1

Step-by-step explanation:

Let the nth term be 116

Here first term=a= 3

common difference= d=8-3=5

So an=a+(n-1)d

=> 116=3+(n-1)×5

=>5( n-1)=116-3

=> 5(n-1)=113

=> (n-1)=113/5

=> n-1=22.6

=> n=22.6+1=23.6

=> n is not a natural number

so 116 is not a term of the given sequence.

hope you got it.

Answer 2

Answer:

Answer: 116 is not a term of this sequence.

a = 3

d = 5

an = 116

a + ( n - 1 ) d = 116

= 3 + ( n - 1 ) 5 = 116

= 3 + 5n -5 =116

= - 2 + 5n = 116

= 5n = 116 + 2

= 5n = 118

= n = 118/5

n = 23.6

hope it helps u....