3 + 8 +13 + ... + x = 1974.
x is
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18
3+8+13+...+x=1974
x is 138
Answered by
4
Solution :-
→ First term = a = 3
→ Common difference = d = 8 - 3 = 5
→ S(n) = 1974 .
So,
→ S(n) = (n/2)[2a + (n - 1)d]
→ 1974 = (n/2)[2*3 + (n - 1)5]
→ 3948 = n(6 + 5n - 5)
→ 3948 = 5n² + n
→ 5n² + n - 3948 = 0
→ 5n² - 140n + 141n - 3948 = 0
→ 5n(n - 28) + 141(n - 28) = 0
→ (n - 28)(5n + 141) = 0
→ n = 28 or (-141/5)
→ n = 28 .
therefore,
→ T(n) = a + (n - 1)d
→ x = 3 + 27 * 5
→ x = 3 + 135
→ x = 138 (Ans.)
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