Question

3√(8/27)^-2 in fraction​

Answer 1

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$( \sqrt[3]{ \frac{8}{27} } ) {}^{ {}^{ - 2} } = ( { \frac{2}{3} } ) {}^{ {}^{ - 2} }$

$= ( \frac{3}{2} ) {}^{ {}^{2} } = \frac{9}{4}$