Math, asked by shyvirajesh, 10 months ago

3√8÷3√2. how to solve this?

Answers

Answered by Raunak008
0
Answer:
\frac{3}{\sqrt{8}}+\frac{1}{\sqrt{2}}=\frac{5\sqrt{2}}{4}
Step-by-step explanation:
Simplify the following:
\frac{3}{\sqrt{8}}+\frac{1}{\sqrt{2}}
We know that √8 = 2√2
\implies\frac{3}{2\sqrt{2}}+\frac{1}{\sqrt{2}}
\implies\frac{3}{2\sqrt{2}}+\frac{2}{2\sqrt{2}}
\implies\frac{3+2}{2\sqrt{2}}
\implies\frac{5}{2\sqrt{2}}
Now we rationalize the denominator to further simplify
\implies\frac{5}{2\sqrt{2}}\times\frac{\sqrt{2}}{\sqrt{2}}
\implies\frac{5\sqrt{2}}{2\times2}
\implies\frac{5\sqrt{2}}{4}
Therefore, \frac{3}{\sqrt{8}}+\frac{1}{\sqrt{2}}=\frac{5\sqrt{2}}{4}

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