Question

(3 ^ 8 ÷ 3 ^ -6) × (9 ^ -2)^3

Answer 1

Hey there! Here is your answer.

$( {3}^{8} \div {3}^{ - 6} ) \times ( { {9}^{ - 2} })^{3} \\= > {3}^{8 - ( - 6)} \times ( {9})^{ - 2 \times 3} \\ = > {3}^{8 + 6} \times {9 }^{ - 6} \\ = > {3}^{14} \times { ({3}^{2} )}^{ - 6} \\ = > {3}^{14 + ( - 12)} \\ = > {3}^{2} \\ = > 9$

Hope this answer will help you!

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