Question

3.8 किलोवाट सामर्थ्य वाले एक इंजन द्वारा 80 मीटर की ऊंचाई पर स्थित एक पानी की टंकी जिसको क्षमता
40 किलोलीटर है, को भरने में लगने वाले समय की गणना कीजिए । पृथ्वी का गुरुत्वीय त्वरण
10 मीटर/सेकण्ड है।
उत्तर : 400 सेकण्ड।​

Answer 1

Answer:3.8=40x10x80/t

3.8xt=4ox10x80

T=40x10x80/3.8

T=40x80/38

T=84.2sec

Explanation:

Answer 2

Time takes to fill tank = 140.35 min.

Given:

A water tank located at a height of 80 meters.

engine of 3.8 kW capacity.

Tank capacity 40 kiloliters.

Gravitational acceleration of the earth  = 10 m/s.

To find:

Time takes to fill tank.

Formula used:

Power = $\rho$QgH

Where     $\rho$ = Density of water = $10^{3}$

               Q = Discharge of engine

               g = Gravitational acceleration of the earth  = 10 m/s.

               H = Height = 80 meters

Explanation:

Power = $\rho$QgH

Power = 3.8 Kw = 3800 W   ...................Given

3800 =  $10^{3}$ ×Q ×10× 80

  Q = $\frac{3800}{10^{3}\times 80 \times 10 }$

 Q = 4.75 × $10^{-3}$ $m^{3}$/s

1000 liter = 1  $m^{3}$

40 kiloliters = 40 $m^{3}$

Tank capacity = Discharge × time

                40   = 4.75 × $10^{-3}$ × time

               time  = $\frac{40}{4.75\times 10^{-3} }$

               time = 8421.05 sec.

              time =$\frac{ 8421.05}{60}$

              time= 140.35 min.

Time takes to fill tank = 140.35 min.

To learn more....

1 Solar power has become a promising source of energy apart from other non-conventional energy. justify

https://brainly.in/question/11138315

2 Calculate the kinetic energy ,potential energy, total energy and binding energy of an artificial satellite of mass 2000 kg orbiting at a height of 3600 km above the surface of the Earth. Given :- G=6.67×10^-11Nm^2/kg^2 R=6400 KM M=6×10^24 kg (ans:KE=40 09×10^9, PE=-80.09×10^9, TE=40.09×10^9, BE=40.09×10^9j)​

https://brainly.in/question/14340755