Question

3.92g of sulphuric acid is dissolved in 400g of water. calculate the molarlity of the solution

Answer 1

Answer:

0.0999 moles

Explanation:

we have 3.92 moles of solute and 200 g of solvent

thus the formula of molarity is = no. of moles of solute/ no of moles of solvent in litre

no of moles of solute is 3.92/98.079 g mol^-1

= 0.03996 moles

thus, 0.03997 moles in 200 g sulphuric acid

0.03996×1000/400 moles per litre

= 0.0999 moles.