Question

3. A 0.20-kg object is attached to a spring with spring constant k = 10 N/m and moves
with simple harmonic motion over a horizontal frictionless surface. At the instant that
it is displaced from equilibrium by -0.050 m what is its acceleration?
a. 1 000 m/s²
b. -40 m/s²
c. 0.1 m/s²
d. 2.5 m/s²
​

Answer 1

Answer:

I think option C!!!!!!!?

Explanation:

option C

Answer 2

Answer:

For a Simple Harmonic Motion,

           F=-kx

           ma=-kx

     0.2 x a=-10 x -0.5

     0.2 x a=0.5

therefore, acceleration a=0.5/0.2=2.5 m/s²

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