Question

3. A 12 cm rod is held between a flashlight
and a wall as shown. Find the length of
the shadow on the wall if the rod is 45 cm
from the wall and 15 cm from the light.
(A) 75 cm
(B) 96 cm
shadow
(C) 48 cm
(D) 60 cm
EO
shadow
​

Answer 1

Hello Mate
I think your answer is 75 centimetre

Answer 2

Answer:

48 cm

Step-by-step explanation:

in ∆ADM & ∆ABF

angle DAM = angle BAF ...(common)

angle DMA= angle BFM (corresponding angles)

Therefore

∆ADM ~ ∆ABF.....(AA test )

AD = DM = AM or DM = AM

AB BF AF BF AF

therefore

6 / BF = 15/60

$= > bf \: = 24 \: cm$

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