Question

3.
A 140 cm long steel bar is acted upon by forces as shown in the figure
below. Determine the total elongation of bar. Take: E = 204 GPa
80 KN
100 KN
3 cm
40 KN 4 cm 60 KN
3 cm
40 cm
60 cm​

Answer 1

Answer:

The action of forces on each part of rod is shown in figure

We know that the extension due to external force F is given by

e=FlAY∴eAB=(60×103)×1.51×2×1011=4.5×10−7m

eBC=(70×103)×11×2×1011=3.5×10−7m and eCD=(50×103)×21×2×1011=5.0×10−7m

The total extension e=eAB+eBC+eCD

=4.5×10−7+3.5×10−7+5.0×10−7

Explanation:

pls mark as brainliest